Question

Mixing Strong Acids and Bases (< 1 of 13 > Constants Periodic Table Imagine that you are in chemistry lab and need to make 1.00 L of a solution with a pH of 2.50. You have in front of you Part A • 100 mL of 7.00x10-2 MHCI, · 100 mL of 5.00x10-2 M NaOH, and • plenty of distilled water. Assuming the final solution will be diluted to 1.00 L , how much more HCl should you add to achieve the desired pH? Express your answer to three significant figures and include the appropriate units. View Available Hint(s) You start to add HCl to a beaker of water when someone asks you a question. When you return to your dilution, you accidentally grab the wrong cylinder and add some NaOH. Once you realize your error, you assess the situation. You have 82.0 mL of HCl and 89.0 mL of NaOH left in their original containers. THÅR O ? Value Units Submit Previous Answers Request Answer

Answer 1

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final pH = 2.5 = -log [ht] [ht] = 102.5 = 3.1622766610-3 molle In Ha [4]=7.00*102 M bu NaOH Cour] =5.000 10-2 m He used = 100-82=18 mL NaOH used = 100-89 = 11ml Let u be the volume of extra ha ( in mL) Hien (HU) min = (wt J here on woment (* Incolumes * 3,16227766810-3 = 7*10-2x18x10 3 – 5x10²x11x10 3 * 316.227766=71+ 70- +7x10-2X VX10-3 v=35.04 mL/Aug