Question

Here is a data set (n = 117) that has been sorted. 56.8 69.8 71.2 73.7 75.5 77. 4 78.7 80.3 81. 8 84. 5 87 88.6 92.4 59.9 70.4 72.2 74 75.6 77.5 78.7 80.5 8 2 85 87.1 88.6 92.7 61.2 70.4 72.3 74.1 75.9 77.7 78.7 80.8 82.2 85.3 87.6 88.9 92.8 62.2 68.4 70.5 70.6 72.4 72.5 74.2 74.3 76.1 76.2 77.8 77. 8 78.9 79.1 | 81 | 81.1 82.2 82.2 86.1 86.5 87.8 87.9 90 90.9 93.5 93.5 68.4 70.7 73 74.8 76. 4 78.1 79.3 81.6 82.2 86.6 88.1 91 94.4 68.5 70. 8 73.1 75.1 76.5 78. 2 79.5 81.6 83.3 86.7 88.1 91 95.2 68.9 68.9 70.8 71 73.5 73.6 75. 1 75.2 76.6 77 78.4 78.6 79.6 79.8 81.7 81.8 84.1 84.5 86.7 86.9 88.2 88.5 91. 2 91.5 95.4 96.9 Find the 37th-Percentile: P37 Preview

Answer 1

Solution 1]P ​​​37​​​​ = (37(n+1/100))th value of observation

P​​​​​​37​​​​ = (37*(117+1)/100)th value of observation

P​​​​​​37 =   (37*118/100)th

P​​​​​​37​​​​ = 44th + 0.66(45th-44th)

= 76.1-0.66(76.2-76.1)

= 76.1+0.066

= 76.166

= 76.2

As per the guidelines I have done the first question please re post the rest. Thank you.