Question

Date: Thursday 09 April 2020: Problem Q1B: Calculate the x- and y-components of the support reactions at A and B. The cables are wrapped securely around the two pulleys, which are fastened together. Note there are two cables, instead of a single continuous cable. (Hint: summing moment at D for the pulley gives the tensions in each cable) - 2 m - 0.3 m 250--- 20 0 .6 m 2 m AL--* m = 200 kg

Answer 1

Sola 12 :3 T-20ora & = 1962N Qu equilibrine- TIXO.G= TGx0.3 1962x0.6 -- ( Tz - 39240 Efn - D. Dx T2 = 39240 Styzoas Dy - T - 1962.N] FRD of AlD' EMAD Dy x 2-DuX2 -FeB XJZ0 FOB = 1962x2-3924x2 dz DadPy B = – 2774-68IN. Apposite to assumed direction) Now 200 AntFR Cosus+ Dozo. A2-1962 + 3924 0 Au- 1962N VE) Efyzon Ay-FeRstumst Dy zo Ay + 1982 + 196220 Ay = -3924N Naw BC' - CAFro Co4° Cr=1962N G - FEB smuro = 1962N - EF ou Bx-191 E ry By = 1962N J