Question

•33 SSM LW A car traveling 56.0 km/h is 24.0 m from a barrier when the driver slams on the brakes. The car hits the barrier 2.00 s later. (a) What is the magnitude of the car's constant acceleration before impact? (b) How fast is the car traveling at impact?

Answer 1

- Sol: where - Given! Vo= 56 kenh & 15.6 m/s. t = 25 O X = 24 m v velocilo q car (Initial) DX= distance from barrier The car away approaches a barrier that is 24m so it decelerales for as before hits the barner. to consland we have to calculate value o - acceleralion : Using kinematical equalion: sx= vt + 1 at? į 2 a cox - Nit) +2 2 ( 24- 15,6x as NI د = as [a= -3.6 m/s2 3.6

(6) The velocity after two seconds Slanning the brakes the relo city time of impact), is given by: ar N = vt at = (15.5 - 3.6 x 2) 8.3 v

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