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5) The reaction PC13(g) + Cl2(g) → PC15(g) has a AS of -170.2 J/molK and a AHⓇ of -87.9 kJ/mol. Assuming the values of AHⓇ an

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Answer #1

∆S° and ∆H ° are given so ∆G° can be calculated as-

Given DS = -17002 Jmolk DH = -8709 kJ/mol = -87900 J/mol. AGO AHO- Tasº at Taroc -87900J - Rocx (-170.2 | . molk mol = 87900

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