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Answer #2

As we know that

Electric poteteial

KQ/R = 10^6

(9*10^9)*Q/0.10 = 10^6

Q = 1.11*10^-5 C

Therefore

4piR^2*Density = 1.11*10^-5

Density = 8.8*10^-5 C/m^2

D option

Required Potetenial = kQ/R

= (9*10^9)*(1.11*10^-5)/(0.20)

= 500*10^3 V/m

A option

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