the original gas V seems to be 25.0 - 15.4 = 9.6
and after the dent 20.4 - 15.4 = 5.0
then
V1P1 = V2P2
9.6(756) = 5.0(P2)
P2 = 1406 mm
I have assumed that the amount of acetone compressed back into
liquid by the drop will be so small that it won't materially affect
liquid volume, at least not to the extent that it will show up in
tenths of gallons
or

Enter your answer in the provided box. A stockroom supervisor measured the contents of a partially...