A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x...

Question

Question

A proton moves perpendicular to a uniform magnetic field B at a speed of 1.90 x 107 m/s and experiences an acceleration of 1.

science physics

Answer 1

Answer #1

The magnetic field and direction

The magnetic force is f = then 9VB Accelration a=fo = qur m B3 am av B = 1.50x10 x 1.67X10 27 6 xio 19 х 150xjo 7 B = 0.824 X

Answer 2

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