12. A frog hops so that it leaves the ground with a speed of vo and...

Question

Question

science physics

Answer 1

Answer #1

a) Vy^2 = uy^2- 2gH

where H = maximum height of the frog

At maximum Height Vy = 0

uy^2 = 2gH

H = uy^2 / 2g

= (Vo*sin $\theta$ )^2 / 2g

13) Time of flight will be double of time taken to reach maximum height

Vy = Uy - gt

0 = Vo* sin $\theta$ - gt

t = Vo sin $\theta$ / g

total time taken = 2t = 2*Vo sin $\theta$ / g

Answer 2

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