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Problem 3 (Needed for Problem 4) A continuous random variable X is said to have an exponential distribution, written Exp(X),

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Ans ③ fx (4) 2 de lo x20 G x<0 A 1) E627= JA mozda ove E(X)= lne **** [*** Jumat = (-1) = 8(493. jak zonder de 34{* ajuste deŐ FELCA) = P[X mo 3 = x 5 o te de -de 7 E-[ediyor -- [ 2*xo_i] -40 P[x> 8++\xxt] = P[x>stt n x>d] . :P[x >] i = P[x> St] P[x>(4) cet xi Time of collapse in a Million Mead 1) P[X3 1] = 0.0000000 2 l e 0.00000002 ē - 0.99999998. = 2.0000000 2 Xio D) E(

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