Given :-
m/z = 82
Formula of M/13 rule
M/13 = n + r /13
The rule of 13 states that the formula of a compound is a multiple n of 13 (the molar mass of CH) plus a remainder r.
Explanation:
The formula is used in interpreting mass spectra.
Molecular formula=CnHn+r
by formula

there for n = 6 and r = 4
C6 H6+4
C6H10
Using the rule of 13, what is the formula of the following hydrocarbon? C 100 Relative...
what are possible structures for each spectra
100 MS 80 - 60 Relative Intensity 40 20- 0 10 20 30 40 60 70 80 50 m/z 100- 80 Relative Intensity 40 20 0 10 15 20 25 30 35 40 50 55 60 65 70 75 80 45 m/z
Using Mass Spec, IR, H-NMR, and C-NMR what would the structure look
like?
Relative Intensity 10 20 30 40 50 60 70 80 90 TERNSMETTANCEI D 4000 NAVENUMBERI 'H NMR PPM 13C NMR 90 80 70 60 50 40 30 20 10 0 PPM PPM DEPT-90 positive DEPT-135 positive Negative Negative Negative Negative Positive
16. A hydrocarbon with a molecular weight of 100 Da (and expected molecular ion at 100 m 2) was analyzed by mass spectrometry and gave the spectra shown below. Based on the MS spectrum and considering possible fragmentation of the hydrocarbon, which of the molecules provided corresponds to this spectrum? 100- m/z = 57 Da Relative Intensity m/z = 85 Da Expected molecular ion (not observed) 10 20 30 40 tillo el origen los 50 60 70 80 90 100...
identify the Unknown by solving the following , Find the
chemical formula using 13 rule , calculate (IHD ) AND FIND THE
Fragmentations , the molecular mass is 86
3505.69 2059.44 1984.62 710.51 462.34 309454 1433.88 848.39 951.84977.00 1294.95 877.02 %Transmittance 1021.28 1371.96 1138.14 1217.98 1647.53 1761.30 4000 3500 3000 2500 2000 Wavenumbers (cm-1) 1500 1000 500 unknown 1.esp Vertical ScaleFactor = 1 Normalized Intensity -729 1008 33 51 9.5 9.0 8.5 80 7.5 70 6.5 60 55 50 45...
16. A hydrocarbon with a molecular weight of 100 Da (and expected molecular ion at 100 m 2) was analyzed by mass spectrometry and gave the spectra shown below. Based on the MS spectrum and considering possible fragmentation of the hydrocarbon, which of the molecules provided corresponds to this spectrum? 100- m/z = 57 Da Relative Intensity m/z = 85 Da Expected molecular ion (not observed) 10 20 30 40 tillo el origen los 50 60 70 80 90 100...
Please label the peaks of the following graphs for the compound
Acetophenone
100 Relative Intensity 100 110 120 Ortofritt 10 20 30 40 50 60 70 80 90 m/z f. NMR Spectrum: 11 10 9 8 5 4 2 1 ppm g. IR Spectrum: THESE TERCEIP HAVENUMERI
identify the unknown from the given spectra
"H-NMR multiplet, 10H triplet, 6H N PPM 13 C-NMR 35 30 25 20 15 10 PPM IR LOD TRATTEET 3000 2000 1500 1000 50 BRYNNERE Mass Spec. 100 80 60 Relative Intensity 40 м 20- 0 ti LO 20 30 40 50 60 70 80 90 100 m/z
Using the NMR, IR, and MS figure out what the compoud is.
**
identify the molecular structure througu NMR, IR and MS
CHEM 100L Lab 3 NMR Problems Unknown 1 CH 0 M-a 102 Relative Intensity 20 30 40 50 70 80 60 m/z water, not part of sample 1-2975-2877 9H, singlet 2H, 3H, quartet triplet ppm Unknown 2 C,H,O tensity 119 Relative 3200-2600 1680V 3H, singlet 2x 2H, doublet 1H, singlet ppm Unknown 3 C,HO, Relative Intensity 3090 3035...
What is the molecular formula and structure? Use the mass,
infrared, proton NMR, and carbon NMR. I have a structure and
formula completed, but I wanted to confirm.
TRANSMETTANCE 41 50 4000 3000 2000 DOST 1000 HAVENUHBERI-1 Mass of molecular ion: 116 100 80- Relative Intensity 40 20- TI Other 10 20 ITHTHIS 30 40 fittihristutt tartott 50 60 70 80 m/z T 110 TITT 120 90 100 200 180 160 140 TTTTTT 120 100 80 60 40 20 ppm...
100- Relative Intensity 10 20 30 40 60 70 80 50 m/z M+ = 68