a] Time taken = angular momentum/Torque = iw/T = (2/5 mr^2*w)/T = (2/5 *1.66*0.43^2*21.9)/0.12 = 22.41 s
b] Time taken = angular momentum/Torque = iw/T = (2/3 mr^2*w)/T = (2/3 *1.66*0.43^2*21.9)/0.12 = 37.34 s
Chapter 09, Problem 83 Chalkboard Video Two spheres are each rotating at an angular speed of...
Two spheres are each rotating at an angular speed of 22.0 rad/s about axes that pass through their centers. Each has a radius of 0.430 m and a mass of 1.64 kg. However, as the figure shows, one is solid and the other is a thin-walled spherical shell. Suddenly, a net external torque due to friction (magnitude = 0.150 N·m) begins to act on each sphere and slows the motion down. How long does it take (a) the solid sphere...
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FULL SCREEN PRINTER VERSION BACK NEET Chapter 09, Problem 83 Chalkboard Video Two spheres are each rotating at an angular speed of 25.3 rad/s about axes that pass through their centers. Each has a radius of 0.440 m and a mass of 1.33 kg. However, as the figure shows, one is solid and the other is a thin-walled spherical shell. Suddenly, a net external torque due to friction (magnitude - 0.480 Nm) begins to act on each sphere and...
Two spheres are each rotating
at an angular speed of 24.6 rad/s about axes that pass through
their centers. Each has a radius of 0.400 m and a mass of 1.68 kg.
However, as the figure shows, one is solid and the other is a
thin-walled spherical shell. Suddenly, a net external torque due to
friction (magnitude = 0.330 N · m) begins to act on each sphere and
slows the motion down. How long does it take (a) the...
Two spheres are each rotating at an angular speed of 24.9 rad/s about axes that pass through their centers. Each has a radius of 0.450 m and a mass of 1.31 kg. However, as the figure shows, one is solid and the other is a thin-walled spherical shell. Suddenly, a net external torque due to friction (magnitude = 0.280 N m ) begins to act on each sphere and slows the motion down. How long does it take (a) the...
Starting from rest, a basketball rolls from the top to the bottom of a hill, reaching a translational speed of 7.8 m/s. Ignore frictional losses. (a) What is the height of the hill (6) Released from rest at the same height, a can of frozen juice rolls to the bottom of the same hill. What is the translational speed of the frozen juice can when it reaches the bottom? (a) Number Units (b) Number Units Click if you would like...