Ans 1 -1) we will use chi-square test for independence
2) Z test for a single mean
3) T-test for comparing means
4) Chi-square test for goodness of fit
Ans 2 ) using minitab> stat>tables >Chi square
we have
Chi-Square Goodness-of-Fit Test for Observed Counts in Variable: Observe count
Using category names in class
Test Contribution
Category Observed Proportion Expected to Chi-Sq
Freshmen 143 0.30 138 0.181159
Sophomore 109 0.25 115 0.313043
Junior 112 0.25 115 0.078261
Senior 96 0.20 92 0.173913
N DF Chi-Sq P-Value
460 3 0.746377 0.862
| class | Observe count | Expected count |
| Freshmen | 143 | 138 |
| Sophomore | 109 | 115 |
| Junior | 112 | 115 |
| Senior | 96 | 92 |
the value of chi square is 0.746
p value is 0.862
option A is true
blem MAA Select an Answer RICA Logged in as yamegandi z Test of a Single Mean...
Where it says “the type of test statistic , chose one) the
options are Z, t , Chi square , F”
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Test the claim that the mean GPA of night students is smaller
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answer please
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Test the claim that the mean GPA of night students is smaller than the mean GPA of day students at the 0.05 significance level, The null and alternative hypothesis would he: HPxPD Ho: Un = yd H: PN PD HH:My CMD HUN MD Hai Py = PD HIPN Po H.Mn + My H.Py > Po H. x > Hp H.: 4n <H H.:Py + P The test is: right-tailed left-tailed two-tailed The sample consisted of 18 night students, with a...
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