Question

Prompt the user for two numbers, call them "x" and "y". "x" must be less than "y" or reject the entry and stop the program. Otherwise, add up all of the numbers between "x" and "y" and display the result. For example:

Enter x: 10
Enter y, larger than x: 20
Total + 10 = 10
Total + 11 = 21
Total + 12 = 33
Total + 13 = 46
Total + 14 = 60
Total + 15 = 75
Total + 16 = 91
Total + 17 = 108
Total + 18 = 126
Total + 19 = 145
The answer is 145

Answer 1

#include«iostream» using namespace std; int main( int x, y int total-0; cout<"Enterx:"; cout<<"Entery, larger thanx:"; cin>>y; if(x>y) coutくぐ'Ignore''.

sample output:

Editable code:

#include<iostream>
using namespace std;

int main()
{

int x, y;
   int total = 0;
cout<<"Enter x: ";
cin>>x;
cout<<"Enter y, larger than x: ";
cin>>y;
if(x>y)
{
    
      cout<<"Ignore";
}

else
{

for (int i=x; i<y; i++)
{
      total+=i;

      cout<<"total+"<<i<<"="<<total<<endl;

}

    cout<<"The answer is "<< total;
}

return 0;
}