Question

With 80% confidence, for sample proportion 0.46 and sample size 26, what is the upper confidence limit with 2 decimal places?

Answer 1

SOLUTION

given : p-0.46. n-26

for 80% confidence level. Za-1.28

formula: Upper con fidence limit for the population proportion. p

$=\hat p+ z_{\frac{\alpha }{2}}*\left \{ \sqrt{\frac{\hat p*(1-\hat p)}{n}} \right \}$

0.46 (1-0.46) 26

0.46 + 0.13

0.59