g of Al (s) at 98° C is placed in 50 g of H2O(0), the final...

Question

Question

science chemistry

Answer 1

Answer #1

-Qhot = Qcold

-Qal = Qwater

-m*C*(Tf-Tal) = mw*Cpw*(Tf-Twater)

substitute

-20*0.90*(26.5-98) = 50*4.184*(26.5-Twater)

-20*0.90*(26.5-98) /( 50*4.184) - 26.5 = -Tw

tw = -20.34

Twate rinitially = 20.34°C

Answer 2

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