Question

Use the t-distribution to find a confidence interval for a mean given the relevant sample results. Give the best point estimate for the margin of error, and the confidence interval. Assume the results come from a random sample from a population that is approximately normally distributed A 90% confidence interval for using the sample results T = 2.9.5 = 0.3, and n = 100 Round your answer for the point estimate to one decimal place, and your answers for the margin of error and the confidence interval to two decimal places. point estimate = margin of error 1 The 90% confidence interval is

Answer 1

7329, S=03 in = 100C -909% The point estimate j = [209] a = X/2 Zara -0.90 -0.10 = 0.05 Zoo5 = 10645 eod of Margin of erra . E = Zal2 s 2 = 196 ts Too E = 0.04935 P. 0.049 0.05 E = 0.05 90% confidence Interval - AI E = 2.9 ± 0.05 = 2.85 , 2.95 90% ez is 2-85 to 2-95)