Question

I'm awful at calculating amounts, I always miscalculate. Could you please help me calculate these nine ketones and aldehydes. I need 3.5mmol converted to grams. Thank you!!!

Answer 1

Sr.No	Aldehyde(R1)	M.F. and M.W.		Ketone(R2)	M.F. And M.W>		Chalcone M.F. and M.W.
1	-CH3	C8H8O(120)		-CH3	C9H10O(134)		C17H16O(236)
2	-CH3	C8H8O(120)		-OCH3	C9H10O2(150)		C17H16O2(252)
3	-CH3	C8H8O(120)		-F	C8H7OF(138)		C16H13OF(240)
4	-Cl	C7H5OCl(140.5)		-CH3	C9H10O(134)		C16H13OCl(256.5)
5	-Cl	C7H5OCl(140.5)		-OCH3	C9H10O2(150)		C16H13O2Cl(172.5)
6	-Cl	C7H5OCl(140.5)		F	C8H7OF(138)		C15H10OClF(260.5)
7	-OCH3	C8H8O2(136)		-OCH3	C9H10O2(150)		C17H16O3(268)
8	-O-CH2-C6H5	C14H12O2(212)		-CH3	C9H10O(134)		C23H20O2(328)
9	-O-CH2-C6H5	C14H12O2(212)		-OCH3	C9H10O2(150)		C23H20O3(354)

2)Conversion of mmol (milimole) into gram :

We know that the molecular weight of given compound expressed in gram corresponds to 1 mole of substance.

And 1 mmol = 1 x 10^-3 mole ----(similar to gram to milligram)

We have 1 mole of compound = molar mass of that compound in gram.

1 mmol of compound = molar mass of that compound in gram x 10^-3.

Hence,

3.5 mmol of compound = 3.5 x molar mass of that compound in gram x 10^-3.

e.g.

For 4-Methylbenzaldehyde molar mass = 120 g

It means 1 mole 4-Methylbenzaldehyde = 120 g 4-Methylbenzaldehyde.

Hence, using above eq.(1)

3.5 mmol 4-Methylbenzaldehyde = 3.5 x molar mass of 4-Methylbenzaldehyde in gram x 10^-3

                                                                                       = 3.5 x 120 x 10-3.

                                                                 = 0.420 g

3.5 mmol 4-Methylbenzaldehyde = 0.420 g                or

3.5 mmol 4-Methylbenzaldehyde = 420 mg.

Hence the conversion of mmol to gram.

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