Question

Vector A⃗ has y-component Ay = +16.0 m . A⃗ makes an angle of 32.0 ∘ counterclockwise from the +y-axis. What is the x component of vector A (Use appropriate unit)? What is the magnitude of A? PLEASE explain your steps I have tried this problem over and over and the computer keeps marking it wrong.

Answer 1

The vector form of A is given by, Ā= A cos oỉ + A sin ej The y-component of A is, 4, = A sin sin e The x-component of A is, A = A cose A cose sin e = A, cote = (16 m ) cot (32° +90°) = -9.9 m Therefore, the x-component of A is -9.9 m. The magnitude of vector A is, A, = A sin e 16 m A - sin (32° +909) = 18.8 m Therefore, the magnitude of vector A is 18.8 m.