Two blocks are suspended over a pulley by a string of negligible mass as shown below....
Two blocks are suspended over a pulley by a string of negligible mass as shown below. The block on the left has a mass of m1, and the block on the right has mass mi, The pulley is a unifonn solid cylinder with mass Mand radius R. The block on the right has a downward acceleration equal to 1/3 the acceleration due to gravity. The tension in the string supporting the mass on the left is T, = 170N and the tension in the string supporting the mass on the right is Ti= 255N. The string does not slip on the pulley.
Homework Answers
given
T1 = 170 N
T2 = 255 N
a = g/3 = 9.8/3 = 3.27 m/s^2
11) b. m2 = 39 kg
T2 = m2*g - m2*a
T2 = m2*(g - a)
m2 = T2/(g - a)
= 255/(9.8 - 9.8/3)
= 39 kg
12) e. 52 kg
net Torque = I*alfa
(T2 - T1)*R = 0.5*M*R^2*a/R
T2 - T1 = 0.5*M*a
==> M = 2*(T2-T1)/a
=2*(255 - 170)/(9.8/3)
= 52 kg
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