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The value of K for the the following reaction is 0.530 at 499 K 6th attempt Part 1 (1 point) See Periodic Table If a reaction
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Answer #1

If we Consider a reversible reaction: aA + bB ⇌ cC + dD
Then the equilibrium constant (Kc) for the reaction expressed in terms of the concentration (mol / litre) may be expressed as:
K c = [C] c [D] d / [A] a [B] b

where a, b, c, d are the number of moles of each reacctant and product involved in the reaction

[C] ,[D] , [A],  [B] are the concentration of products and reacctants respectively at equilibrium

The calculated concentration of NO2 at equilibrium is 0.0152 M

t(22)2. No2 2 2.

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