Two CSMA/CD stations are each trying to transmit long (multiframe) files. After
each frame is sent, they contend for the channel, using the binary exponential backoff
algorithm. What is the probability that the contention ends on round k, and what is the
mean number of rounds per contention period?
Please type answer, please do not hand write. Thank you
The probability that contention ends on round k,
Using backoff exponential algo
At round one they have single slot and they both try to transmit in
that and hence collides
At round two there are 2 slots waiting for 0 and 1
At i th round station can choose to wait in any 2^i-1 slots
Probability of choosing any one slot in ith period is
1/(2^i-1)
probability of both station choosing same slot is (1/2^i-1) *
(1/2^i-1) = 1/2^2(i-1)
Total probability of choosing any of the 2^i-1
slot is hence P = 2^i-1 * (1/2^2(i-1)) = 1/2^i-1
this is probability of collision in ith round
for success on kth round we should have k-1 round in collison and
kth round on success
that is {product i:1 to k-1 }(1/2^i-1) * (1- 1/2^i-1)
Two CSMA/CD stations are each trying to transmit long (multiframe) files. After each frame is sent,...
Two CSMA/CD stations are each trying to transmit long files. After each frame is sent, they contend for the channel using binary exponential backoff algorithm. What is the probability that the contention ends on round k, and what is the mean number of rounds per contention period?
suppose two devices using CSMA/CD and the binary exponential backoff algorithm have just sent transmission that have each experienced collision Twice. what is tye probability that both devices will transmit successfully during the bext two time slots where n=3.