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9. Generate a hypothetical titration curve for the titration of 50.0 mL of 0.1 M HCI with 0.25 M NaOH at 25 °C. (12 points)
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AND I suppose, we want to titrate 01 M suppose HCl with an ate 0.1 M He with olm Naone PH, before adding Now PH = -log(0.1) [ HCl & Noon - Noct +4₂0 Instal change 5 Equelbum - So, now base in excess New conch. of bale = 1 50 +6 por= -log (6.09) = 0.01

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