Question

Module SeqServices Uses None Syntax Exported Constants None Exported Access Programs Out Exceptions Routine name In is Ascending isIn Bounds interpLin interpQuad index X: R" XRRR Semantics State Variables None State Invariant None

Write a library module that provides services for processing sequences. It should consist of a python code file named SeqServices.py. The specification for this module is given in the two pictures.

Answer 1

def isAscending(X):
for i in range(len(X)-1):#loop till n-1 where n is len(X)
if X[i]>X[i+1]:#if a pair found out of order, return false
return False
return True#if no pair found out of order, return true
def isInBounds(X,x):
return x>=X[0] and x<=X[-1]#return true if x>=first element and x<= last element
def interpLin(x1,y1,x2,y2,x):
out = (float)(y2-y1)/(x2-x1)
out = out*(x-x1) + y1
return out#return value of out calculated using the formula
def interpQuad(x0,y0,x1,y1,x2,y2,x):
out = (float)(y2-y0)/(x2-x0)
out = out*(x-x1) + y1
out += (x-x1)*(x-x1)*(y2-2*y1+y0)/(2*(x2-x1)*(x2-x1))
return out#return value of out calculated using the formula
def index(X,x):
for i in range(len(X)-1):
if x >= X[i] and x<X[i+1]:#finds the i for which X[i]<=x<X[i+1]
return i#return i
return len(X)-1#else return last index of X

Refer to image below for better understanding and proper indentation.

File Edit Selection Find View Goto Tools Project Preferences Help 1 def isAscending(X): range(len(X) 1):#loop till found len(X) return for į in if n-1 out where of n is X[i] x(1+1]:#if a pair order, false 4. return False return True#if no pair found out of order, return true 6 def isInBounds (X,x): return x>-X[0] and x(-X[-1]#return true if x>=first element and x(2 last element 8 def interpLin(x1,y1,x2,y2,x): out (float) (y2-y1)/(x2-x1) out out* (x-x1) yl return out#return value of out calculated using the formula 10 12 def interpQuad(xe,ye,x1,y1,x2,y2,x): 13 14 15 16 17 def index(X, x): 18 19 20 21 out (float) (y2-y8) /(x2-xe) out out* (x-x1) yl out +(x-x1)*(x-x1) (y2-2 y1+y) (2 (x2-x1) (x2-x1)) return out#return value of out calculated using the formula for i in range(len (X)-1): if :-X[1] return i#return x and x.x(1+1] : #finds the i for which X[i]<3x<x(i+1] i return len(X)-1telse return last index of X Line 22, Column 1 Spaces: 4 Python

Sample output:

>>>isAscending (X) False >>>isAscending (X) True >>isInBounds (X, 3) True >>isInBounds (X, 4) True >>> interpLin (1,2,2,4,3) #equation of line 6.0 >>> interpQuad (1,1, 2,4, 3, 9,4) #equation of 16.0 >>>index (X, 2) y-2x. Should expect 6. y®X"2. Should expect 16

The comments in the code are only for you understanding. You can remove them if you want.

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