Homework Answers
CO + 2H2 -----> CH3OH deltaH = -18KJ
1. Adding of CO: If concentration of molecules on left side increases, equiibrium shifts to right side & viceversa
Therefore adding of CO, increases the formation of CH3OH
2. Removing H2: If concentration of molecules on left side decreases, equiibrium shifts to left side & viceversa
Therefore removing of H2, decreases the formation of CH3OH
3. decreasing the volume of container: if volume of a reaction decreases, then the equilibrium shifts to the side having least number of moles of molecules and viceversa
therefore, if volume decreases, formation of CH3OH increases
4. Adding a catalyst: No effect on equilibrium
5. Increasing the temperature: if temperature increases, for exothermic reaction equilibrium shifts to backward and for endothermic reaction shifts to forward
therefore, the with increase in temperature formation of CH3OH decreases
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