Question

The next 7 questions concern the following summary data for a pinprick response study for which the population mean for withdrawing the hand in response to a pinprick is known to be H=250ms. The study examined eyeblink responses for patients at risk of developing Parkinson's Disease, and hypothesized that early Parkinson's Disease patients will exhibit longer response times, which, if true, would help with early diagnosis of the disease. n 30 EX 7638 EX2 1944904 20. What is the mean pinprick reaction time for the sample (round to the nearest whole number)[2 marks) 21. Calculate SS, the sum of squared deviations from the mean (round to the nearest whole number)[3 marks) 22. Calculates, the sample variance (round to the nearest whole number) (2 marks) 23. Calculates, the sample standard deviation (round to the nearest whole number) (1 mark] 24. Calculate the test statistic for the sample mean (round to 2 decimal places) (2 marks] 25. What is the appropriate critical value, assuming alpha=.05 for this study? (1 mark] 26. What would be the decision for this hypothesis test? [1 mark]

Answer 1

(20)

Mean is given by:

(Round to integer)

Η Σx 7638 30 = 255

So,

Answer is:

255

(21)

Sum of Squared Deviations from mean, SS is given by:

(Round to integer)

Ss – Σx?_ (ΣΧ) - 1944904 76382 - = 1944904-1944634.8 = 269 30 n

So,

Answer is:

269

(22)

Sample Variance (s²) is given by:

(Round to integer)

2 _ 200 _,

So,

Answer is:

9

(23)

Sample Standard Deviation (s) is given by:

&= =s

So,

Answer is:

3

(24)
SE = s/$\sqrt{n}$

= 3/$\sqrt{30}$

= 0.5477

Test statistic is given by:

t = (255 - 250)/0.5744

= 8.70

So,

Answer is:

8.70

(25)

One Tail - Right Side Test

= 0.05

Invalid Equation

ndf = n - 1 = 30 - 1 = 29

From Table, critical value of t = 1.6991

So,

Answer is:

1.70

(26)
Since calculated value of t = 8.70 is greater than critical value of t = 1.70:
Reject null hypothesis. The data support the claim that early Parkinson's Disease patients will exhibit longer response times.