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An aqueous solution has a pOH of 4.41 (1) What is the pH of this solution? (2) What is the hydroxide ion concentration in thi
An aqueous solution has a pH of 4.41 (1) What is the pOH of this solution? (2) What is the hydroxide ion concentration in thi
An aqueous solution has an hydroxide ion concentration of 2.62 10-2M. (1) What is the hydrogen ion concentration in this solu
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Answer #1

a. 1. pH = 14 - pOH = 14 - 4.41 = 9.59

2. pOH = -log([OH-])

4.41 = -log([OH-])

Solving, [OH-] = 3.89 * 10-5 M

3. pH = -log([H+]) = 9.59

SOlving, [H+] = 2.57 * 10-10 M

b.

1. pOH = 14 - pH = 14 - 4.41 = 9.59

2. pOH = -log([OH-]) = 9.59

SOlving, [OH-]= 2.57 * 10-10 M

3. pH = -log([H+])

4.41 = -log([H+])

Solving, [H+] = 3.89 * 10-5 M

c. We have the relation: [OH-] * [H+] = 10-14

2.62 * 10-2 * [H+] = 10-14

Solving [H+] = 3.82 * 10-13 M

pOH = -log([OH-]) = 1.58

pH = -log([H+]) = 12.42

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