16) first option 2.6 mol of Mg is the correct answer
17) fifth option 1.0 mol of CO2 is the correct answer
Explanation is attached

Question 16 According to the following equation convert 2.6 moles of Clto moles of Mg. Mg...
Трето Benzene (CH) burns in air according to the following equation shown below. How many moles of O, are required to react with 0.76 mol of CH? 2 CH (1) + 15 02(g) 12 CO2()+6H2O(g) mol O2
Question 24 According to the following equation convert 16.0 grams of Co, to grams of CH4 CHA. 30, 200, + 2 H2O 1280 320 1440 18 05.09g 0.3649 O 1269 8.00 g 0.1829 U Question 25 According to the following equation convert of 6.21 grams of CH4 to grams of water. 2 CH4 + 19 0212 CO2 + 14 H2O 186 of [320) [440] [180] 1.30 g 9.109 43.59 0.1869 208 9 Question 26 A chemical reaction test
Question 3 Propane (C3H8) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) -- 3 CO2(g) + 4H2O(g) Arxn = -2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3H8 a. -104.7 kJ/mol ob. +1407.7 kJ/mol C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol
Question 3 Propane (C3Hg) undergoes combustion according to the following thermochemical equation: C3H8(g) + 5 O2(g) - 3 CO2(g) + 4H2O(g) AHrxn=-2043.0 kJ Substance Heat of Formation (kJ/mol) CO2(g) -393.5 H2O(g) -241.8 O2(g) 0 C3H8(g) ? Calculate the standard enthalpy of formation of propane C3Hg a. -104.7 kJ/mol O b. +1407.7 kJ/mol O C. -1407.7 kJ/mol O d. +104.7 kJ/mol o e. -4190.7 kJ/mol uestion 4 Consider the evaporation of liquid water to water vapor at 125°C. What is true...