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General Relativity Question 1

Consider a satellite in a circular orbit at a dist

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Answer #1

The acceleration due to gravity on the satellite is, g an (R+h) therefore., g (R+h) (6.37x10* m (6.37x10° mr-100x103 m) 9.81Therefore, 9.81 =(1 s) V9.509 1015698 s The clock on satellite slower compared to clock on earth per second is, T= 1.015698

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