± Gravitational Force of Three Identical Masses Part A What is the magnitude of the net...

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Answer 1

Answer #1

m1 = 6500 kg

m2 = 6500 kg

m3 = 6500 kg

x1 = 0

x2 = -120 cm = -1.2 m

x3 = 330 cm = 3.3 m

force exerted by m2 on m1 F21x = -G*m1*m2/x1^2

F21x = -6.67*10^-11*6500*6500/1.2^2

F21x = -0.00195 N

force exerted by m3 on m1 F31x = -G*m1*m3/x1^2

F31x = 6.67*10^-11*6500*6500/3.3^2

F31x = 0.00026 N

Fgrav = F21x + F31x

Fgrav = -0.00195 + 0.00026

Fgrav = -0.00169 N

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Answer 2

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