JKJHomework Answers
Since its infinite we can replace the second rung and on with
Req
so Req is in parallel with 1 ohm
R = Req/(Req + 1)
so Req = Req/(Req + 1) + 1
Req - 1 = Req/(Req + 1)
Req^2 - 1 = Req
Req^2 - Req - 1 = 0
use quadratic formula
Req= ( 1 + sqrt(5))/2 = 1.618 ohms
1+R*1/(R+1) = R
R^2-R-1 =0
Req = 1.618 ohm
b) 12*(0.68/1.68)^n =V
W = V^2/R <1
so V<1
4th resistance
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