Question

RD R1 69.5k 2k out M1 Rvin Cin VDD Vin NTJ 200 3.3 Vin R2 RS |СЬ 500 30.5k AC 10m 2 W 20 L 0.18 CGD 2pF, CGs8pF, CDB -1.5pF, CsB-2.5pF. Find the transfer funcitons of the circuit for Vout/Vin and draw the bode plot of the frequency response for the above circuit. Include relevant poles and zeroes as well as the calculations for how they were obtained. Be sure to note the 3db bandwidth of the circuit.

Answer 1

Given that equation is rightarrow The given Transfer functions of the circuit is V_out /V_in. rightarrow The given analysis we Replace large capacitor with Slc and small cup rightarrow The given medium frequency analysis and disconnect. \r\n rightarrow The given CS with by pan capacitor amplest rightarrow given frequency is (votage). Av_m = -g_m R_4 V_Gs = 3.3 times 30.5/69.5 + 30.5 V_Gs = 1.000Gs rightarrow given that ln cos = 200 mu A/v_2 w/L = 20/0.18 v_TH = 0.5v rightarrow Here gm = 0.112 Ohm Therefore = g_m = 11.2 g_m Ohm Therefore Hence Arm = -(11.2 times 10^-3)(2 times 10^3) Avm = 22.25 Therefore The equation is Proved