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PHYS202, College Physics 2, Spring 2019 KHW(20) Problem 20.04 -2.40 10- C. The particle is given an initial horizontal Correc
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Solution)

Here, magnetic force= weight of the particle

So, Bqv=mg

Or, B= mg/qv

Mass, m=0.18 g=0.18*10^-3 kg

Charge, q=2.31*10^-8 C

Velocity, v=4*10^4 m/s

Hence, B=(0.18*10^-3 kg)*(9.8)/(2.3*10^-8 C)*(4*10^4 m/s)

B=1.909 T (Ans)

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