Question

3.43 Using the superposition principle, find the magnitude and polarity of the voltage across the 7-mA source in Fig. ure P3.43. 1 ΚΩ 2 k22 SV 7 mA © 3.49 In the circ or absorbed?) by analysis; (c) the sun prefer the most? T 3k92 4 k2 Figure P3.43

Answer 1

The given circuit is 2 kr TMAQ Vo: v W 3kr 4 kr

Superposition theorems- - It states that in a linear circuit with element in Produced by more sources, the voltage is the circuit is the sum of voltages each source acting independently, AM

when "sv" voltage source is alone active : - other voltage sources are short and current sources are open: . (ка . • + 4 Кл Von + Кл 3kr SX6k Voltage division 6KHк 3к Vo = 30 6v" source is alone when active- w Ki a aka 6V 4 kr Voz = - 6x4K 44t 2k+4K Nog = -2.4V

when Tma" is alone active: uw tekr M car CMA sa nur M 3km 4 ki 7m x 4K current I = = 2.8mA. 66 +4K f current division rule] Ixok = 16.8V. 2. Nos Finally Total voltage accross "7ma" is Vo = Voit Voz t Vo3=3-2.4+16.8 T: V. = 17.40 So, the arrow direction of current source is tve" of the voltage accross it.