Question

Please solve by only Unit Force method/deflection method

Sec. 9.5 9-13. Determine the reactions at the supports. Assume A and C are pins and the joint at B is fixed connected. El is constant 12 kN/m B 12kN/m 4 m 6 m Prob. 9-13

Answer 1

Support Reaction For loading diag Sigma Fx = 0, (rightarrow +ve) H_A + H_C = 1/2 times 12 times 6 = 36 kN -(1) Sigma Fy = 0, (p +ve) R_A + R_C - 12 times 4 = 0 R_A + R_C = 48 kN -(2) Sigma M_A = 0, [ +ve] R_C times 4 + H_c times 6 - 1/2 times 2 times 6 times (6/3) - 12 times 4 times 2 = 0 4 R_C + 6 H_C = 16 B -(3) For unit load diag Sigma Fx = 0, H_A = 1 unit Sigma M_A = 0, R_C times 4 - 1 times 6 = 0 R_C = 1.5 unit Sigma Fy = 0 R_A - R_C = 0 R_A = R_C = 1.5 unit \r\n Concept unit load method deflation (s) = integral M_x - M/EI dx Where M_x rightarrow Bending moment at x - x due to applied load