Question

Find the total capacitance in micro farads of the combination of capacitors shown in the figure below. mu F

Answer 1

Here 0.3 $\mu$ F and 10 $\mu$ F are in series. So total capacitance of both

= $\frac{0.3 \times 10}{0.3 + 10}\mu F$

= 0.29 $\mu F$

Now this 0.29 $\mu F$ is in parallel with 2.5 $\mu F$

So total capacitance = 0.29 $\mu F$ + 2.5 $\mu F$ = 2.79 $\mu F$

TOTAL CAPACITANCE OFTHE COMBINATION = 2.79 $\mu F$

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