Question

19) A gymnast dismounts from the balance beam by leaping nearly straight up from the 1.3 m high beam at a speed of 4.0 m/s, doing a complete twist, and then landing on the mat close to the beam. a. How high above the beam did she rise? (10 points) b. What was her downward velocity just before hitting the mat? (10 points) C. She "sticks" the landing and her body comes to a complete stop in 0.4 seconds from the time her foot first touches the mat. What average acceleration does her body experience during that time? (10 points)

Answer 1

beam T 13 mm guzo mpee max heigh is reached when _54-4m/ her final wel in zero. - mat so, aum/see, vzo, a=g210m/s2 using v2=4²+zag 0 2 42 225 = oom als=o8mas above the bean 29 b speed while landing can be calculated using same Equation from her top most point as initial point here u zo mpee v=? s=201m a galom/s2 V22 42+ 2003 svo J2x10x 21 = 6.48m/sec Tv 2 60 48 m/seel Timetaken to come to rest at = 4 see augaurs ont = 648-0 = 16.2 m/s2. - .4