sample mean = 213.4552
sample Standard deviation = 44.81542
N=50
alpha = .05
SEM = 6.337857477
For each of the following hypothesis testing problems, manually calculate the t-statistic, use the 5% level of significance (alpha = 0.05), determine the rejection region, determine the p-value of the t-test, use the 95% confidence interval in part (c) to make a decision about whether or not to reject the null hypothesis.
Test the null hypothesis that the true mean is 225 versus the alternative hypothesis that the true mean is different from 225. Symbolically,
H0:μ=225 against H1:μ≠225
Test the null hypothesis that the true mean is 220 versus the alternative hypothesis that the true mean is different from 220. Symbolically,
H0:μ=220 against H1:μ≠220
sample mean = 213.4552 sample Standard deviation = 44.81542 N=50 alpha = .05 SEM = 6.337857477...
A sample mean, sample standard deviation, and sample size are given. Use the one-mean t-test to perform the required hypothesis test about the mean, μ , of the population from which the sample was drawn. Use the P-value approach. Also, assess the strength of the evidence against the null hypothesis. sample mean = 24.4, s = 9.2, n=25, H0: μ = 26, Ha : μ , 26, α = 0.05 Options: A: Test statistic: t = -0.87. P-value = 0.1922....
Consider the following hypothesis test:H0 : μ = 16Ha : μ ≠ 16A sample of 50 provided a sample mean of 14.34. The population standard deviation is 7. a. Compute the value of the test statistic (to 2 decimals).b. What is the p-value (to 4 decimals)? c. Using α = .05, can it be concluded that the population mean is not equal to 1?d. Using α = .05, what are the critical values for the test statistic (to 2 decimals)?e. State the rejection...
A random sample from normal population yielded sample mean=40.8 and sample standard deviation= 6.1, n = 15. H0: μ = 32.6, Ha: μ ≠ 32.6, α = 0.05. Perform the hypothesis test and draw your conclusion. Question 3 options: Test statistic: t = 5.21. P-value=0.00013. Reject H0. There is sufficient evidence to support the claim that the mean is different from 32.6. Test statistic: t = 5.21. P-value=1.9E-7 (0.00000019). Do not reject H0. There is not sufficient evidence to support...
A random sample from normal population yielded sample mean=40.8 and sample standard deviation= 6.1, n = 15. H0: μ = 32.6, Ha: μ ≠ 32.6, α = 0.05. Perform the hypothesis test and draw your conclusion. A. Test statistic: t = 5.21. P-value=0.00013. Reject H0. There is sufficient evidence to support the claim that the mean is different from 32.6. B. Test statistic: t = 5.21. P-value=1.9E-7 (0.00000019). Reject H0. There is sufficient evidence to support the claim that the...
A sample of size 36 is taken from a population with unknown mean and standard deviation 4.5. In a test of H0: μ = 5 vs. Ha: μ < 5, if the sample mean was 4, which of the following is true? (i) We would reject the null hypothesis at α = 0.01. (ii) We would reject the null hypothesis at α = 0.05. (iii) We would reject the null hypothesis at α = 0.10.
1. Test the claim that the mean GPA of night students is significantly different than 2.4 at the 0.2 significance level. The null and alternative hypothesis would be: a) H0:μ=2.4 H1:μ>2.4 b) H0:μ=2.4 H1:μ<2.4 c) H0:p=0.6 H1:p<0.6 d) H0:p=0.6 H1:p>0.6 e) H0:p=0.6 H1:p≠0.6 f) H0:μ=2.4 H1:μ≠2.4 2. The test is: a) left-tailed b) right-tailed c) two-tailed 3. Based on a sample of 35 people, the sample mean GPA was 2.44 with a standard deviation of 0.04 The test statistic is:...
The observations from a random sample of n = 6 from a normal population are: 13.15, 13.72, 12.58, 13.77, 13.01, 13.06. Test the null hypothesis of H0:μ=13 against the alternative hypothesis of H1:μ<13. Use a 5% level of significance. Answer the following, rounding off your answer to three decimal places. (a) What is the sample mean? (b) What is the sample standard deviation? (c) What is the test statistic used in the decision rule? (d) Can the null hypothesis be...
A sample mean, sample standard deviation, and sample size are given. Use the one meant test to perform the required hypothesis test about the mean, , of the population from which the sample was drawn. Use the P-value approach. Also, assess the strength of the evidence against the null hypothesis. x-22,298, s=14200, n = 17, HO: P = 30,000, Ha# 30,000 a -0.05. Test statistic: 224. P.value 0.0200. Reject the null hypothesis. There is sufficient evidence to conclude that the...
A random sample of 100 observations from a population with standard deviation 18.99 yielded a sample mean of 93.4. 1. Given that the null hypothesis is μ=90 and the alternative hypothesis is ?>90μ>90 using ?=.05α=.05, find the following: (a) Test statistic == (b) P - value: (c) The conclusion for this test is: A. Reject the null hypothesis B. There is insufficient evidence to reject the null hypothesis C. None of the above 2. Given that the null hypothesis is μ=90...
From a sample of 37 stolen watches, you find that the mean cash value is $950. The standard deviation for your sample is $90. Test the null hypothesis that your sample came from a population whose mean cash value (Mu) is $1,000 against the alternative hypothesis that Mu is different than $1,000. Use alpha = .05. Formally state the alternative and the null hypothesis for this test (3 pts) What is the critical value(s) for this test? (3 pts) Compute...