Question

C++ Programme

Write a function that receives, as arguments, a pointer to a double array, as well as the number of elements: in the array(int). The function must use pointer operations and calculate the standard deviation of the elements in the array. The function returns the standard deviation to the calling statementſ Use the function in main( to display its operation. | Example: array = (11.2, 2.4, 3.13, 16.4, 5.8, 9.22, 4.9, 10.5, 6.5, 2.99) std Dev(array) = 4.249367 ZWI Hint: x, denotes the ith element in the array.

Answer 1

Please find the required C++ script as the following:

//========================================================

#include <iostream>

#include <iomanip> // For controlling double precision

#include <math.h>

using namespace std;

#define size 10

double stdDev(double* arr,int arr_size)

{

int i;

double sum_n=0,sum_n2=0,std_val;

for(i=0;i<arr_size;i++)

{

sum_n=sum_n+arr[i]; // Calculating sum(xi)

sum_n2=sum_n2+(arr[i]*arr[i]); // Calculating sum(xi^2)

}

std_val = sqrt((sum_n2/arr_size)-pow(sum_n/arr_size,2));

return std_val;

}

int main() {

// Input array

double arr[size] = {11.2,2.4,3.13,16.4,5.8,9.22,4.9,10.5,6.5,2.99};

// Function call and output

cout <<setprecision(7)<<"Standard Deviation: "<<stdDev(arr,size)<<"\n";

return 1;

}

//===================================================

output:

Standard Deviation: 4.249367

Hope this helps!

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