Question

3. Find the area of the surface of revolution obtained by rotating the graph of y = 2x around the x-axis for the interval 0 S
0 0
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Answer #1

about X-axis y = 2x² ocx e 56 dy dx 42 1 +1622 dx 156 SAZ 272 J1 +1672 dy ds=litet ? dx = 2011 4rt Lito qe J162°41dx 457.035

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