Question

A 5.51 g mixture contains both lithium fluoride, LiF, and potassium fluoride, KF. If the mixture contains 3.56 g fluorine, what is the mass of the KF in the mixture? Ø mass of KF: 1.08 g

Answer 1

Mam of KF+ Lif= 5. 5igm Assume Mass of lif: P Man of KF E 5. 5 - P КЕ Molar Man of * 58 gel 39 + 19 = 58 KF Contain im F 19 gm of I gm of KA Contain ot Is i gm of 5* *(5-31-P]gm of F -> (5.51-4) of Contain gm Molar Man of Lif 7 + 19 = 26 mol 86 of lif Contain ) 3 2 оғр gan of Lif Contain F gm gm m of 26 5.51-2 of Lif Contain gm 9 996 exC P) Total F in the mixture 19 58 5.51–p) + 19 P = 3.56 996 0.397586P + 0-73077 P= 3.56 5.51 X 0.397.586 1.805 + 0.4031839 p = P = 3.56 It pa 3.56-1-80S 4.35 286 0.403183 & = 4.353 gm Man of KER 5.518- 4.353 9" 11 1.157 gm