Question

4. Find the unknown resistance R, so that maximum power is delivered to it. Also find the maximum power. 1.2592 i, 1 60 512 24v

Answer 1

Given ciswit I 1.252 ix sr is ro Ch24V for finding maximum Power transfer, we must first find the thevenin ewivalent ůrwit across Load terminal AB. 24V thevenin een verden 31 T rewit acron • A thevenin euivalent where, Rih MA Vth = open itwir vollage across Load terminals Ith (I) Rth thevenin Resislame seen from lood terminal o Steps Finding Vth Volleyeat this nade = Vith ; 125 i 52 zeven Ilx fr § 241 - B by kuli - (x(6+5) -24 +3 ix = 0 1 9x = -24.-3A So; Vth = 3 ix - 6 ix -3x = (-3%E3) With a gul

Step2 finding Rh, Since, dependent voltage source is present Do, we will be finding Roh by "Test voltage approach" 1.250 V Ix here, Test voltage Soine is applied at Load touninal. So that Rina Vt IT 'Notes - Replau independent 1 Sources with their internal Resistants "Apply Nodal aralyms at vi 1 V₂ VT À V₂ - 3x + x = 0 - 1. 256 om vo [ites + ] - - [1-4] 50 01 Vs 10966) - 0.8V+ +0.519.20 And, Na = {xx5 So, sin (0.96) - 0.8 V1 + 0.59x20 5.33 ix = 0.8V4 - since, - IT = VT - V Vt-six 1.25 1.25 ar 1.25 Iy = VT -six - Q VÍ - J. 25II (2) VT, 5.33 Put value of ix prome," (2) ine? ) 5.33 VT - 1:25 IT 50-8V7 L : 5 1- 3325 CV1 - 12 SIT] = V1 0.3325 V1 = 1.665625 IT or Rin=vt = 5 IT =

to thevenin equivalent cirwit is I Rh=sh mpA Vih=9v Now, for maximum Power traufen i RL =Rm ad [RL = 50 AH Vete? Maximum power, Pmax (911 4.05 W FRti 4.05 W .. 4x5 29 Poy 24 05w