Question

What mass of sulfuric acid can we produce by the following reaction

          S₈(s) + 12 O₂(g) + 8 H₂O(l) → 8 H₂SO₄(s)

if we have 384.3 g of S₈(s), 350.3 g of O₂(g), and 324.8 g of H₂O(l)?

(b) (3 points) We must do the combustion of what mass of propanol, C₃H₈O(l), to produce 42.5 g of products? Combustion is the reaction of a substance with O₂(g) to produce CO₂(g) and H₂O(l)?

Answer 1

$ (5 + 12 02 (9) + 84,0 (0) — 84,504 (2) No. of moles of Sg mass of So MN OF Sg 256.48 384.2 g 1.50 mol moe No. of moles of 350.39 2 10.95 mol 31.898 g/mol No of moles of H₂O = 324.89 18.03 mol 18.015 g moet 1 mol Sg NEEDS Se Needs 12 moe low mo - 1.50 mol Sg x Х 18 mol O2 12 mol O2 Imom se 8 mol H₂O NEEDS 12 mol o 18.08 moe H20 hecos 2 Liminna PRESENT 2 18:03 mol H₂O x 12 mol O₂ 27.0 mol O2 8 mol Ho so o BUT Only 10.95 mol O₂ REAGENT. 12 mol O2 PRODUCES 10,95 mol 2x 8 mol H₂SOA 12 mol og 8 mor Ho sog. 10.95 mol O₂ PRODUCES Х 7.3 moe H sod HISOA MASS of PRODUCED = Haso so x 9W 4. H₂SO4 4 #moles 7.3 molx 981089 almal $16.0g

5) С. НО (0) + 0, (0) - 20, (0) + + 40 (2) moe C3 H₂O PRODULES Ам) 4 mХ Чо 1 3 moi or 2x 49 MASS OF PRODUus! | 32 4 g/mol 4 mt x 18 elmet - 129 0 1 mol C3 50 producrs. х So ca so Pe0ow le! 204 6 42.5 4 Робои 4 1 mol C₂ H₂O PRODUCED Ви з 42.5 Э 204 О. 208 mx C2 НО mw of 250 ma! of Coнo : #mol C3H₂Ox О. 208 теңx bo b4; • Olme г 12:54