Question

OD (LOADED REGION 101 501

L=8in
S=1.75in
D=0.44in
P=3500Lbs
I need 1a) Stress in bar at load application region and, 2a) Stress in bar away from the load application region

Answer 1

The normal stress caused by an axial load is given by the equation: 1a) At the loaded region, the stress is the highest as the area of application is lower than the total are of the bar, sing the area of the circular region: 0=7d2 0 = 35001b 7(0,44) a = 23018psi = 23,018kpsi 2a) However, as we get further away from this point, the stress averages out in the cross section, decreasing rapidly. Using the area of the square cross section: 3500lb o=7702 = 1142psi = 1,142kpsi