Question

This is a C++ code, ıt works successfully, I want to convert to C language

It is very emergency!! Please help

#include<iostream>

using namespace std;

void findWaitingTime(int processes[], int n,

int bt[], int wt[], int quantum)

{

int rem_bt[n];
for (int i = 0 ; i < n ; i++)
rem_bt[i] = bt[i];
   int t = 0;

while (1)
{
bool done = true;
for (int i = 0 ; i < n; i++)

{
if (rem_bt[i] > 0)

{
done = false;
if (rem_bt[i] > quantum)

{
t += quantum;   
rem_bt[i] -= quantum;
}

else
{
t = t + rem_bt[i];
wt[i] = t - bt[i];
rem_bt[i] = 0;

}
}
}

if (done == true)
break;
}
}

void findTurnAroundTime(int processes[], int n, int bt[], int wt[], int tat[])

{
for (int i = 0; i < n ; i++)
tat[i] = bt[i] + wt[i];
}

void findavgTime(int processes[], int n, int bt[], int quantum)

{
int wt[n], tat[n], total_wt = 0, total_tat = 0;
findWaitingTime(processes, n, bt, wt, quantum);
findTurnAroundTime(processes, n, bt, wt, tat);
cout << "Processes "<< " Burst time " << " Waiting time " << " Turn around time\n";

for (int i=0; i<n; i++)

{
total_wt = total_wt + wt[i];
total_tat = total_tat + tat[i];
cout << " " << i+1 << "\t\t" << bt[i] <<"\t "<< wt[i] <<"\t\t " << tat[i] <<endl;

}
cout << "Average waiting time = " << (float)total_wt / (float)n;
cout << "\nAverage turn around time = " << (float)total_tat / (float)n;

}
int main()
{
int processes[] = { 1, 2, 3};
int n = sizeof processes / sizeof processes[0];
int burst_time[] = {10, 5, 8};
int quantum = 2;
findavgTime(processes, n, burst_time, quantum);

return 0;

}

Answer 1

PLEASE NOTE : FEEL FREE TO ASK ANY DOUBTS by COMMENTING

QUESTION, WHICH WAS GIVEN:

Computer Science This is a C++ code, it works successfully, I want to convert to C language It is very emergency!! Please help

::::::::::::::::::::::::::::::::::::::::::::::::::: CODE in C Language :::::::::::::::::::::::::::::::::::::::::::::::::::

#include <stdio.h>
#include <stdbool.h>

void findWaitingTime(int processes[], int n,int bt[], int wt[], int quantum)
{
   int rem_bt[n];
   int i=0;
   for (i = 0 ; i < n ; i++){
       rem_bt[i] = bt[i];
   }

    int t = 0;
   while (1)
   {
       bool done = true;
       for (i = 0 ; i < n; i++)
       {
           if (rem_bt[i] > 0)
           {
               done = false;
               if (rem_bt[i] > quantum)
               {
                   t += quantum;
                   rem_bt[i] -= quantum;
               }
               else
               {
                   t = t + rem_bt[i];
                   wt[i] = t - bt[i];
                   rem_bt[i] = 0;
               }
           }
       }
       if (done == true){
           break;
       }
   }
}

void findTurnAroundTime(int processes[], int n, int bt[], int wt[], int tat[])
{
   int i=0;
   for (i = 0; i < n ; i++){
       tat[i] = bt[i] + wt[i];
   }
}

void findavgTime(int processes[], int n, int bt[], int quantum)
{
   int wt[n], tat[n], total_wt = 0, total_tat = 0,i=0;
   findWaitingTime(processes, n, bt, wt, quantum);
   findTurnAroundTime(processes, n, bt, wt, tat);
   printf("Processes Burst time Waiting time Turn around time\n");
   for (i=0; i<n; i++)
   {
       total_wt = total_wt + wt[i];
       total_tat = total_tat + tat[i];
       printf(" %d\t\t%d\t%d\t\t%d\n",i+1,bt[i],wt[i],tat[i]);
   }
   printf("Average waiting time = %.4f\n",(float)total_wt/ (float)n);
   printf("\nAverage turn around time = %.4f\n",(float)total_tat/ (float)n);
}
int main()
{
   int processes[] = { 1, 2, 3};
   int n = sizeof processes / sizeof processes[0];
   int burst_time[] = {10, 5, 8};
   int quantum = 2;
   findavgTime(processes, n, burst_time, quantum);
   return 0;
}

::::::::::::::::::::::::::::::::::::::::::::::::::: OUTPUT :::::::::::::::::::::::::::::::::::::::::::::::::::

FOR GIVEN CODE:

D:\Program.exe Processes Burst t Waiting time Turn around time Nort NHN Average waiting time = 12 Average turn around time = 19.6667 -------------------------------- Process exited after 0.09545 seconds with return value o Press any key to continue ...

FOR UPDATED C-Language CODE

D:\Program.exe Processes Burst tim Waiting time Turn around time HAM NENO Επώο Average waiting time = 12.0000 Average turn around time = 19.6667 - - - - - - - - - - - - - - - - - - Process exited after 0.04936 seconds with return value o Press any key to continue ...

::::::::::::::::::::::::::::::::::::::::::::::::::: CODE in EDITOR :::::::::::::::::::::::::::::::::::::::::::::::::::

Program.c 1 #include <stdio.h> 2 #include <stdbool.h> 4 void findWaitingTime(int processes[], int n, int bt[], int wt[], int quantum) 59 { 6 int rem_bt[n]; int i=0; for (i = 0; i<n; i++) { rem_bt[i] = bt[i]; int t = 0; while (1) 14 15 bool done = true; for (i = 0; i<n; i++) 17 if (rem_bt[i] > 0) done = false; if (rem_bt[i] > quantum) t += quantum; rem_bt[i] -= quantum; 27 t = t + rem_bt[i]; wt[i] = t - bt[i]; rem_bt[i] = 0; 31 F 34 35 if (done == true) { break; 36F

етапил по пл OOOOO 37 E B 38 L) 39 40 void findTurnAroundTime(int processes[], int n, int bt[], int wt[], int tat[]) 41 P { 42 int i=0; 43 for (i = 0; i<n; i++){ 44 tat[i] = bt[i] + wt[i]; 45 46 L3 47 48 void findavgTime(int processes[], int n, int bt[], int quantum) 49 { int wt[n], tat[n], total_wt = 0, total_tat = 0,i=0; findWaitingTime (processes, n, bt, wt, quantum); findTurnAround Time (processes, n, bt, wt, tat); printf("Processes Burst time Waiting time Turn around time \n"); for (i=0; i<n; i++) 55 total_wt = total_wt + wt[i]; total_tat = total_tat + tat[i]; printf("%d\t\t%d\t%d\t\t%d\n", i+1, bt[i], wt[i], tat[i]); 59 printf("Average waiting time = %.4f\n", (float)total_wt/ (float)n); printf("\nAverage turn around time = %.4f\n", (float)total_tat/ (float)n); 62 L} 63 int main() 64 = { int processes[] = { 1, 2, 3}; int n = sizeof processes / sizeof processes [0]; int burst_time[] = {10, 5, 8}; int quantum = 2; findavgTime(processes, n, burst_time, quantum); return 0; 71 L} pr

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