Question

in i 14.3A - Ideal Gas Law - SHOW WORK FOR FULL CREDIT A 5.00 mol sample of oxygen gas has a pressure of 110 kPa at 22'C. Calculate volume A 1.5 mol sample of radon has a volume of 21.0 L at 33°C. What is the pressure? A sample of neon has a volume of 3.45 L at 25°C and 90 kPa. Calculate moles. A cavern contains 224 L of methane gas at a pressure of 150 kPa and a temperature of 315 K. How many grams of methane (CH.) does this contain? When the temperature of a rigid hollow sphere containing 685 L of helium gas is held at 621 K, the pressure of the gas is 189 kPa. How many moles of helium does the sphere contain? Determine the volume occupied by 0.582 mol of a gas at 15°C if the pressure is 81.8 kPa. What pressure is exerted by 0.450 mol of a gas at 25°C if the gas is in a 0.650-L container? If 4.50 g of methane gas (CH) is in a 2.00-L container at 35°C, what pressure is in the container? What is an ideal gas? Under what conditions do real gases deviate most from ideal behavior? ono oi.

Answer 1

1) Ideal gas law - PV = nRT Pressure (P) in unit atm , moles un Temperature Volume (1) in letre , R = 0.0821 Latm k moli Given: n = 5 mol , T = 22°C = 295k P = 110 kPa - 110 atm [1 atm= 101.325 kPa] 1010325 V= nRT = 5 x 0.0821 x 295 x 101.325 = (111.54LL P 110 (2.) n = 1.5 mol, V=21L, T=33= 273 +33 = 3068 P= nRT = 1.5x 0.0821 × 306 = 11079 atm 21 (3.) V = 3.451, T = 25°C= 298k , P = 90 kPa = 90 atm 101-325 - PV = 90 x 3.45 = 10-125 mole A RT 101.325 x 0.0821 × 298 (4.) V = 224 L , P = 150 atm, T = 315k 101.325 n = PV = 150 x 224 = 12.82 moles RT 101.325 x 0.0821 X 315 Molar mass of crly = 16g/mol Mass of methane (g) = moles y moler mass = 12.82% 16 - 205.159 / (5.) V = 685L , T = 621k , P = 189 atm 101.325 V = 189 x 685 = /25.06 moles 101.325x 0.0821 x 621 (6) n = 0.582 mol , T= 15c = 288k, P = 81.8 atm 101325 v nRT - 0.582 X 0-0821 X288 X101-325 n = 3 nz V p 81-8 (17.04L

7.) m = 0.450 , T = 25C = 288k, v=0.650 L P= nRT = 0.450x 0.0821 x 298 0.650 8.) Mass = 4.50g, V=2L, T=35°C - 308k Molar mass of Urly = 16 g/mol Moles = Given Mass - 4.50 = (0.281 mole) Molar Mass P= nRT = 0.281 X 0.0821 X 308 = 3.55 atm V P: ARY Molar Mass - 4.50 - 10.2

9) Ideal gas is a hypothetical gas whose molecules occupy negligible volume and has no interaction.

10) Real gases deviate from ideal gad behavior because their molecules has forces of attraction between them and occupy space.