Calculate the standard cell potential (E_cell) for: H2O2(aq) +ClO2(aq) --> ClO2^- + O2(g). (Basic solution). AND...

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Question

Calculate the standard cell potential (E_cell) for:

H2O2(aq) +ClO2(aq) --> ClO2^- + O2(g). (Basic solution). AND

Fe(s) +2Fe^3+(aq) --> 3Fe^2+ (aq)

science chemistry

Answer 1

Answer #1

(a): H2O2(aq) +ClO2(aq) --> ClO2^- + O2(g). (Basic solution).

Oxidation - half cell: H2O2(aq) + 2OH^-(aq) ------- > O2(g) + 2H2O + 2e- ; E⁰(oxi) = + 1.10 V

Reduction - half cell: 2ClO2(aq) + 2e- ------ >2 ClO₂^-(aq) ; E⁰(red) = + 0.95 V

Hence E⁰(cell) = E⁰(oxi) + E⁰(red) = 1.10 V + 0.95 V = 2.05 V (answer)

Note: Use the E value given in your notebook to get exact answer.

(b): Fe(s) +2Fe^3+(aq) --> 3Fe^2+ (aq)

Oxidation - half cell: Fe(s) ------- > Fe²⁺(aq) + 2e- ; E⁰(oxi) = + 0.44 V

Reduction - half cell: 2Fe³⁺(aq) + 2e- ------ > 2Fe²⁺(aq) ; E⁰(red) = + 0.77 V

Hence E⁰(cell) = E⁰(oxi) + E⁰(red) = 0.44 V + 0.77 V = 1.21 V (answer)

Answer 2

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