a) Non-empty : Since (1,2) belongs to this set, it is Non-empty
b) Closure property of Addition : Suppose (x1,x2) and (x3,x4) are in this set then x2 = 2(x1) , x4 = 2(x3) , adding these two, x2 + x4 = 2(x1 + x3) , so (x1+x3,x2+x4) also is in this set
c) Property of scalar multiplication : Suppose (x1,x2) is in this set and k is some scalar. Then since x2 = 2(x1) , multiplying both sides by k, we get k(x2) = k(2(x1)) = 2(k(x1)) . So (k(x1), k(x2)) also is in this set.
So it is a subspace.
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