Question

3. A room has 6000 W of recessed fluorescent light fixtures without lens on from 6 am to 6 pm. The air flows from the lights through a ducted return. Compute internal cooling load using radiant time series (RTS) from light at 5 pm, assuming that 20% of heat from the light is absorbed by the return air stream without becoming room load. Consider light weight room construction and non-carpeted floor with 50% glass wall. (30 points)

Answer 1

So!? about 20% of heat air. As per the given Condition from light is Convected to return a c = 0.2qHG - O Calculate the Convective heat gain using the following formula to the return by where angt heat gain from light fixtures. Substituce the value of Gooo w for QHG. in EQ? O AC: 0.2 x6000 de : 1200w, & The heat space to any hour this is form 6am to 6.p.m are Equal ave . Calculate the remaing gain to space at any hour . by using following formula - q = QHG - qe where . ae Convective heat gal to the return air a ais heat gain in Spac. ZHG = 6000 and 2c = 12000 q 6000 w - 1200w 4800 watt Thus, the heat sain to the Spaa at spm 48oow