Question

C++ Programming

determine the roots of the equation with errors of less than 0.1% for x values between -5 and 5. you MUST NOT use the "if" statement in your code.

f(x) 0.2 + sin2x 1 + cos x .log (x + 20)

Answer 1

Copy pastable code :

#include <iostream>

#include<cmath>

using namespace std;

double f(double x)

{

return (0.2 + sin(x)*sin(x))/(1+cos(x)*log10(x+20));

}

int main()

{

double x = -5;

double value;

double step = 0.2;

double arr[100];

int i =0;

while(abs(x)<5){

value = f(x);

switch (abs(value)<0.1){

case true :

arr[i] = x;

i+=1;

break;

}

x+=step;

}

switch (i>0){

case true:

cout<<"Root is near : ";

for(int j = 0; j<i ; j++){

cout<<arr[j]<<", ";

}

break;

case false:

cout<<"No root found";

}

cout<<endl;

}

Code Snippet :

1 2 3 4 5 6 #include <iostream> #include<cmath> using namespace std; double f(double x) { return (0.2 + sin(x)*sin(x))/(1+cos(x) *log10(x+20)); //return the value of function at x } int main() ܒ 8 9 LO 1 2 _3 4 5 L6 -7 8 double x = -5; //x inititilize double value; double step = 0.02; // Check for root at start double arr[100]; // to store roots int i =0; 9 while(abs(x)<5){ // loop when -5<x<+5 20 value = f(x); //calculate value 22 3 24 5 26 27 8 29 EO switch (abs (value) <0.1){ //of value meet error you can change the error case true : arr[i] = x; //add the root to array i+=1; break;} X+=step; // next step } 2 53 34 55 56 37 58 59 10 switch (i>0){ case true: // if root cout<<"Root is near : "; for(int j = 0; j<i ; j++){ //print all the root cout<<arr[j]<<", "; } break; 12 case false: cout<<"No root found"; // else no root 13 14 15 16 17 +8 19 50 } cout<<endl;

Output of the code :

(base) deeplearningcv@deepak-LINUX :-/Documents$ gcc code.cpp -lstdc++ -lm Textbook Retur (base) deeplearningcv@deepak-LINUX:-/Documents$ ./a.out Root is near : -0.16, -0.14, -0.12, -0.1, -0.08, -0.06, -0.04, -0.02, -1.80342e-14, 0.02, 0.04, 0.06, 0.08, 0.1, 0.12, 0.14, 0.16, (base) deeplearningcv@deepak-LINUX :-/Documents$ :